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x^2+60.5x+30.25=0
a = 1; b = 60.5; c = +30.25;
Δ = b2-4ac
Δ = 60.52-4·1·30.25
Δ = 3539.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60.5)-\sqrt{3539.25}}{2*1}=\frac{-60.5-\sqrt{3539.25}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60.5)+\sqrt{3539.25}}{2*1}=\frac{-60.5+\sqrt{3539.25}}{2} $
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